Logic Masters Deutschland e.V.

Lief, the Univeres, and Everythign

(Eingestellt am 31. August 2024, 06:00 Uhr von SSG)

SSG is turning 42? That can't be rihgt.

Normal sudoku rules apply; but, every clue is wrogn. Any clue that fully obeys one of the following rules is not wrogn.

Ambiguous Thermos: Digits along a gray line must strictly increase from one end to the other.

Ascending Starters: A clue outside the grid applies to the sum of the first run of ascending digits from the position of the clue (i.e. the sum from the first digit encountered until digits are no longer ascending). This may be only a single digit.

Entropic Lines: Along a peach line, every group of three consecutive cells must contain one low {1,2,3}, one medium {4,5,6}, and one high {7,8,9} digit.

Killer: Digits in a cage may not repeat and must sum to the given total.

Modular Lines: Along a teal line, every run of three digits must all have different remainders under division by 3.

Nabner: No two cells on a yellow line may contain either the same digit or consecutive digits.

Parity Lines: Along a red line, adjacent digits may not have the same parity.

Renban: Digits along a purple line form a non-repeating consecutive set.

Quadruples: Every digit in a circle must appear at least once in the surrounding four cells.

SudokuPad

Lösungscode: Row 5 + Column 2 (18 digits)

Zuletzt geändert -

Gelöst von virus_dave, Palfly Kampling, ZornsLemon, DiMono, SKORP17, ashisstuff, blackjackfitz, cybers, mew_rocks, fjam, jkuo7, mse326, darkdrium06, Sotehr, nmmc123, mackant1, Felis_Timon, tome_coelho, ... juventino188, BeeBoi, lmdemasi, roflsalot, SudokuHero, MrQubo, dpsy, QuiltyAsCharged, k2u5as, OGRussHood, amarins, bansalsaab, madhupt, taide, Puzpensu, meixia, sarabtx, Sewerin, Uhu, SashaBu
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Kommentare

am 1. September 2024, 00:41 Uhr von blackjackfitz
As good as a Pan Galactic Gargle Blaster (and twice as potent!)

am 31. August 2024, 08:02 Uhr von virus_dave
Quite fun, start to finish. Thank you @SSG!

Schwierigkeit:4
Bewertung:88 %
Gelöst:44 mal
Beobachtet:0 mal
ID:000JKX

Variantenkombination Online-Solving-Tool

Lösung abgeben

Lösungscode:

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