As an extension of the "Renbanomino" series, I created this puzzle using german whisper relationships.
RulesNormal sudoku rules apply. Place one "omino" (an orthogonally connected group of shaded cells) in each box such that:
Partial Example
The partial example shows how two adjacent boxes might be filled:
Play on SudokuPad
Please leave a comment if you enjoy this puzzle.
Lösungscode: All 9 digits from row 1.
am 23. August 2024, 23:33 Uhr von elpadrinoIV
@DieHard, thank you for clarifying some rules.
It's still unclear to me yet whether all unshaded cell on any given box must be orthogonally connected. e.g., if shaded cells in box 1 are only those in column 2, it complies with the criteria that there's one "omino" (an orthogonally connected group of shaded cells) in box 1, but in box 1 the unshaded cells would not be connected (and could still be connected when taking into account the whole grid).
Can you clarify this rule please?
Die Hard: The rules state that you have to place "one" omino in each box. So it is not valid to have (for example) R2C4+R2C6+R3C6 as the only shaded cells in box 2. That would be two ominos in box 2. The rules don't place any restrictions on unshaded cells (other than they must be orthogonally connected across the entire grid, and there cannot be any 2x2 areas of unshaded cells).
am 11. August 2024, 19:25 Uhr von sahi1l
Very nice puzzle! I too was a little thrown by the wording of the rules, and would probably drop the mention of ominos at the top, and instead add a rule at the bottom that says "the shaded cells in each box must form a single omino" or something like that.
am 5. August 2024, 17:45 Uhr von Franjo
Wonderful idea + excellent setting = perfect puzzle, a pleasure to solve this gem. Thank you so much for sharing.
am 5. August 2024, 01:26 Uhr von sacklunch
@DieHard, can you clarify which “omino” rules apply within individual boxes, vs those which apply to the entire grid? For example, could R1C2 and R2C2 be the only shaded cells in box 1? That would seem to meet the rules as written, but the shaded section in box 1 would not connect to shaded cells in other boxes. Also, must the connected shaded cells differ by at least 5 only within each box, or also across box borders?
Die Hard: All of the "such that" rules apply to the entire grid (with the obvious exception of the circle counts). So, for example: All shaded cells in the entire grid must be orthogonally connected, all orthogonally connected shaded cells in the entire grid must differ by at least 5, etc.
am 4. August 2024, 17:20 Uhr von wuc
Tough break in. Then smooth rest. To me 3.5 stars. Very clever puzzle. Great fun thx.
am 4. August 2024, 14:31 Uhr von rameshsrivats
Superb puzzle. Tough, but very satisfying.
am 4. August 2024, 13:09 Uhr von lmdemasi
Very interesting. The ways in which this was different from a standard yin-yang was cool.
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Bewertung: | 94 % |
Gelöst: | 30 mal |
Beobachtet: | 1 mal |
ID: | 000J6X |