Logic Masters Deutschland e.V.

Quadrarrows

(Eingestellt am 11. Mai 2024, 23:02 Uhr von Jay Dyer)

Rules

  • Normal sudoku rules apply.
  • The sum of digits on an arrow must equal one of the digits in the four cells surrounding the connected circle. If more than one arrow on the same circle have the same sum, then said sum must appear at least that many times in the cells surrounding the circle.

Solve in Sudokupad.

Lösungscode: Column 2


Gelöst von KNT, Fool on Hill, tuturitu, killer_rectangle, CHRosenthal, Jesper, Mr_tn, Snookerfan, bansalsaab, SKORP17, Piatato, SudokuHero, sanabas, AKernel, AvonD, Vodakhan , galgamer, ProRock, Glasgow, ... juventino188, kevinlimanta, H-K, dennischen, Samish, Uhu, MrQubo, DavidH, Leilalu222, QuiltyAsCharged, widjo, redfoot, Semla, michaal94, darrenfwl, Mikemerin, ahmadasiabi, windmill, BlacknWhite
Komplette Liste

Kommentare

am 12. Juni 2024, 23:17 Uhr von DavidH
Neat idea that doesn't seem nearly constrained enough to produce a unique solution, but it somehow comes together to make a really fun puzzle.

am 14. Mai 2024, 02:15 Uhr von madhupt
This is a new rue set but makes for an extremely smooth solve. I’m sure Simon will solve it very soon on CtC and that will be one delightful video. Can’t wait to compare his solve path with mine which I’m confident will coincide with his.

am 13. Mai 2024, 00:16 Uhr von marcmees
new & nice. thanks

am 12. Mai 2024, 18:42 Uhr von sanabas
Extremely elegant solve

am 12. Mai 2024, 17:21 Uhr von SudokuHero
This is the first time I've seen this constraint, and it is extremely inventive. I love the way all the arrows worked together.

am 12. Mai 2024, 16:53 Uhr von Piatato
Awesome puzzle, thanks!

am 12. Mai 2024, 13:33 Uhr von Jesper
Very smooth!

am 11. Mai 2024, 23:35 Uhr von Fool on Hill
Beautifully clean and fresh logic

am 11. Mai 2024, 23:05 Uhr von KNT
enjoyed testing this puzzle, very very good execution!

Schwierigkeit:4
Bewertung:97 %
Gelöst:76 mal
Beobachtet:8 mal
ID:000I1R

Variantenkombination Online-Solving-Tool

Lösung abgeben

Lösungscode:

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