Normal Sudoku rules apply. Digits in a cage sum to the total in the top left corner (if given) and do not repeat. In each 3x3 box, each cage in that box has a sum that is in a 1:2 ratio with the sum of at least one of the other cages in that box.
This is the first puzzle I've made that I'm actually publishing, if you have any feedback, let me know!
Lösungscode: Bottom row
am 22. August 2023, 18:03 Uhr von geronimo92
Ragna : the most important word in the ruleset is "Each"
am 4. August 2023, 20:17 Uhr von Ragna
The little words "at least" in the ruleset are important. :-)
am 4. August 2023, 09:27 Uhr von MrBusDriver
confusing with the box 3 with 3 cages.. i knew that the 7 cell was 28 so other in box 3 was14/7 or double 14
am 3. August 2023, 19:58 Uhr von sujoyku
This was a fun solve. Thank you for setting and sharing, Cablr!
am 3. August 2023, 19:25 Uhr von Cablr
Revised to remove the other possible solution (my bad!) Thanks to @sujoyku for their help.
am 3. August 2023, 18:55 Uhr von sujoyku
Thank you for your reply. Here is my complete solution code (row 1 to 9 from left to right):
165842739324957168798361425546718392981523674237496851819675243652134987473289516
The cages in box 1 have totals of 12 and 24, the cages in box 2 totals of 6 and 12, the cages in box 3 totals of 14, 14 and 28, the cages in box 4 have totals of 8 and 4, in box 5 the cage sums are 8 and 16, in box 6 the sums are 14 and 28, in box 7 they are 8 and 4, in box 8 the sums are 8 and 16 and in box 9 the sums are 7, 14 and 28. Is there something invalid?
Response: I must apologise, it appears there's an oversight in the construction leading to two possible solutions, yours and the intended solution. I'll be taking this puzzle down and fixing it. Thank you for your help.
If you're interested, the difference is in box 2. The intended sums are 7 and 14, not 6 and 12, but clearly at some point I accidently made 6 and 12 viable.
am 3. August 2023, 18:10 Uhr von sujoyku
I have found a solution code which is rejected but seems to satisfy all constraints as far as I can see. Do the rules exclude two cages in the same box having equal sums when they are in a 1:2 ratio with another cage in that box?
Response: The rules do not exclude that. I.e. if three cages were in a box, and one has a sum of 12, both of the others could be 6, or 24, or a combination thereof. Also, one could be 12, and the other then must be 6 or 24.
Have you ensured that the constraint is true in every 3x3 box?
am 3. August 2023, 17:54 Uhr von StefanSch
Interesting puzze, but you have to read the rules verry carefully.