Oops! All Schrödinger
(Eingestellt am 2. April 2023, 03:40 Uhr von louisng114)
・Fill each row and column with the digits 0-9. To this end, all cells are Schrödinger cells, i.e., each cell contains two digits. The number in the corner of each cage indicates the difference between the two numbers of the cell. For example, if a cell contains digits 7 and 9, then the cage should have a 2 in the corner.
・At least one of the cells in the corner contains the digit 8.
・(There is a logical path; bifurcation is not necessary)
・At least one of the cells in the corner contains the digit 8.
・(There is a logical path; bifurcation is not necessary)
Lösungscode: Smaller of the two digits in each cell of row 3 (left to right), then larger of the two digits in each cell of column 4 (top to bottom). No spaces or comma.
Zuletzt geändert am 18. April 2023, 07:45 Uhr
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Kommentare
am 18. April 2023, 07:45 Uhr von louisng114
Removed "New" tag
Zuletzt geändert am 2. April 2023, 11:52 Uhr
am 2. April 2023, 11:49 Uhr von Paquet Voleur
Note for Paquet Voleur: double-checking the rules and your solution is not enough. You also need to read what solution code to enter. In this case, the LARGER values of column 4...
am 2. April 2023, 04:47 Uhr von louisng114
@Paquet Voleur
The solution code is correct.
am 2. April 2023, 04:16 Uhr von Paquet Voleur
Would you mind double-checking your solution code?
